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Structure of Atom

Student Quick Revision Focus High-yield exam revision guide for CBSE Boards, NEET, JEE Main & Advanced. Covers discovery of subatomic particles, Thomson & Rutherford models, Planck's Quantum Theory, Photoelectric effect, Bohr's Model, De Broglie dual nature, Heisenberg Uncertainty Principle, Quantum Numbers, and Electronic Configurations!

1. Discovery of Subatomic Particles

1.1 Discovery of Electron (Cathode Rays)

Discovered by J.J. Thomson (1897) via discharge tube experiment at low pressure and high voltage.

Cathode Ray Tube Experiment

1.2 Discovery of Proton & Neutron

2. Early Atomic Models

2.1 Rutherford's $\alpha$-Particle Scattering Experiment

Rutherford Alpha Scattering Experiment

3. Wave & Particle Dual Nature of Radiation

3.1 Electromagnetic Wave Parameters

$$\mathbf{c = \nu \lambda} \quad \text{and} \quad \mathbf{\bar{\nu} = \frac{1}{\lambda}}$$
Electromagnetic Spectrum

3.2 Black Body Radiation Graph

Ideal body absorbing/emitting all frequencies. Intensity vs wavelength peak shifts to shorter wavelength at higher temperature (Planck's quantum concept).

Black Body Radiation Intensity Graph

3.3 Planck's Quantum Theory & Photoelectric Effect

Planck's Energy Quantum Formula Radiant energy is emitted or absorbed in discrete packets called quanta (photons): $$\mathbf{E = h\nu = \frac{hc}{\lambda}}$$ Where $h = \text{Planck's constant} = \mathbf{6.626 \times 10^{-34}\text{ J s}}$.
Photoelectric Effect Experiment
Einstein's Photoelectric Equation Ejection of electrons when light of frequency $\nu > \nu_0$ strikes metal surface: $$\mathbf{E = W_0 + K.E._{max} \implies h\nu = h\nu_0 + \frac{1}{2} m_e v^2 = e V_0}$$ Where $W_0 = h\nu_0 = \text{Work Function}$, $\nu_0 = \text{Threshold Frequency}$, $V_0 = \text{Stopping Potential}$.

4. Bohr's Model for Hydrogen Atom

Bohr Model of Hydrogen Atom
Bohr's Postulates & Derived Formulas 1. Quantization of Angular Momentum: $$\mathbf{m v r = \frac{n h}{2\pi}} \quad (n = 1, 2, 3...)$$ 2. Radius of $n^{\text{th}}$ Orbit: $$\mathbf{r_n = 0.529 \times \frac{n^2}{Z} \text{ \AA} = 52.9 \times \frac{n^2}{Z} \text{ pm}}$$ 3. Velocity of Electron: $$\mathbf{v_n = 2.18 \times 10^6 \times \frac{Z}{n} \text{ m/s}}$$ 4. Total Energy of Electron: $$\mathbf{E_n = -13.6 \times \frac{Z^2}{n^2} \text{ eV/atom} = -2.18 \times 10^{-18} \times \frac{Z^2}{n^2} \text{ J/atom}}$$

4.1 Hydrogen Line Spectrum & Rydberg Equation

Transitions of Electron in Hydrogen Atom
Rydberg Formula for Spectral Lines: $$\mathbf{\bar{\nu} = \frac{1}{\lambda} = R_H Z^2 \left( \frac{1}{n_1^2} - \frac{1}{n_2^2} \right)}$$ Where $R_H = \text{Rydberg Constant} = \mathbf{109,677\text{ cm}^{-1} = 1.097 \times 10^7\text{ m}^{-1}}$.
Spectral Series of Hydrogen Atom
Series$n_1$$n_2$Spectral Region
Lyman1$2, 3, 4...$Ultraviolet (UV)
Balmer2$3, 4, 5...$Visible
Paschen3$4, 5, 6...$Infrared (IR)
Brackett4$5, 6, 7...$Far Infrared
Pfund5$6, 7, 8...$Far Infrared

5. Towards Quantum Mechanical Model

5.1 De Broglie Dual Nature of Matter

De Broglie Dual Nature of Matter
$$\mathbf{\lambda = \frac{h}{p} = \frac{h}{m v} = \frac{h}{\sqrt{2 m (K.E.)}} = \frac{h}{\sqrt{2 m q V}}}$$

5.2 Heisenberg's Uncertainty Principle

Heisenberg Uncertainty Principle
$$\mathbf{\Delta x \cdot \Delta p \ge \frac{h}{4\pi} \implies \Delta x \cdot (m \Delta v) \ge \frac{h}{4\pi}}$$

Conclusion: Impossible to determine position and velocity of microscopic particle simultaneously with absolute accuracy $\Rightarrow$ rules out Bohr's fixed circular orbits!

6. Quantum Mechanical Model & Quantum Numbers

6.1 Radial Probability Distribution Curves

Radial Probability Distribution Graphs

6.2 Shapes of Atomic Orbitals

Shapes of s, p, d Atomic Orbitals
The Four Quantum Numbers
Quantum Number Symbol Allowed Values Significance
Principal $n$ $1, 2, 3, 4...$ Main shell, size & energy. Total orbitals $= n^2$, Max $e^- = 2n^2$.
Azimuthal $l$ $0$ to $(n-1)$ Subshell shape ($s=0, p=1, d=2, f=3$). Orbital angular momentum $L = \sqrt{l(l+1)}\frac{h}{2\pi}$.
Magnetic $m_l$ $-l \text{ to } +l$ Spatial 3D orientation. Total orientations $= (2l + 1)$.
Spin $m_s$ $+\frac{1}{2}, -\frac{1}{2}$ Electron spin orientation. Spin angular momentum $= \sqrt{s(s+1)}\frac{h}{2\pi}$.

7. Rules for Electronic Configuration

7.1 Aufbau Principle

Aufbau Principle Energy Order Diagram

Orbitals are filled in increasing order of energy via $(n + l)$ rule. Order: $1s < 2s < 2p < 3s < 3p < 4s < 3d < 4p < 5s...$

7.2 Pauli Exclusion & Hund's Rule of Maximum Multiplicity

Hund Rule Electronic Configuration Example
Exceptional Configurations (High-Yield) Half-filled & fully-filled subshells possess extra stability due to high exchange energy & symmetry:
Chromium ($\text{Cr}, Z=24$): $[\text{Ar}] 3d^5 4s^1$ (not $3d^4 4s^2$)
Copper ($\text{Cu}, Z=29$): $[\text{Ar}] 3d^{10} 4s^1$ (not $3d^9 4s^2$)
Student Quick Revision Self-Test Q1 (JEE Main): Calculate the energy and radius of electron in 1st orbit of $\text{He}^+$ ($Z=2$).
Solution:
$E_1 = -13.6 \times \frac{2^2}{1^2} = \mathbf{-54.4\text{ eV}} = \mathbf{-8.72 \times 10^{-18}\text{ J}}$.
$r_1 = 0.529 \times \frac{1^2}{2} = \mathbf{0.2645\text{ \AA}} = \mathbf{26.45\text{ pm}}$.
Q2 (NEET): How many radial nodes and angular nodes are present in $4p$ orbital?
Solution: For $4p$: $n=4, l=1$.
Angular Nodes $= l = \mathbf{1}$.
Radial Nodes $= n - l - 1 = 4 - 1 - 1 = \mathbf{2}$.
• Total Nodes $= n - 1 = 3$.