🔎 1. What is Congruence?
Two figures are congruent (≅) if they have the same shape AND same
size. When superimposed (placed on top of each other), they match exactly.
Congruent vs. Similar:
• Congruent (≅): Same shape + SAME size. Example: Two identical stamps.
• Similar (~): Same shape, DIFFERENT size (covered in higher classes). Example: A photo and
its enlargement.
Corresponding Parts: When two triangles are congruent, their CPCT hold true:
CPCT = Corresponding Parts of Congruent Triangles (are equal)
If △ABC ≅ △PQR, then: AB=PQ, BC=QR, AC=PR and ∠A=∠P, ∠B=∠Q, ∠C=∠R
📋 2. Criteria for Congruence of Triangles
SSS
Side-Side-Side
All three sides of one triangle equal to corresponding three sides of the other triangle. No angle
needed!
SAS
Side-Angle-Side
Two sides AND the included angle (the angle between the two sides) are equal. Angle must be
BETWEEN the two sides!
ASA
Angle-Side-Angle
Two angles AND the included side (side between the two angles) are equal.
AAS
Angle-Angle-Side
Two angles and a non-included side are equal. (Since 3rd angle can be derived, this works!)
RHS
Right Angle-Hypotenuse-Side
Only for RIGHT triangles: Right angle + Hypotenuse + one leg are equal.
⚠️ What does NOT prove congruence
• AAA (Angle-Angle-Angle) — proves SIMILARITY only, not congruence! (Triangles could be
different sizes)
• SSA (Side-Side-Angle) — DOES NOT work! The angle must be included (SAS) or hypotenuse
(RHS) for right triangles.
✏️ 3. Worked Examples
Example 1: In △ABC and △DEF: AB=DE=5cm, BC=EF=7cm, AC=DF=9cm. Are they congruent?
All three sides are equal. So by SSS criterion, △ABC ≅ △DEF. By CPCT, ∠A=∠D, ∠B=∠E,
∠C=∠F.
Example 2: In △PQR and △XYZ: PQ=XY=6cm, ∠P=∠X=40°, PR=XZ=8cm. Are they congruent?
Two sides and the included angle (∠P is between PQ and PR). By SAS criterion, △PQR ≅
△XYZ.
Example 3: In △ABC, AB=AC (isosceles) and AD bisects ∠A. Prove △ABD ≅ △ACD.
In △ABD and △ACD: AB=AC (given), ∠BAD=∠CAD (AD bisects ∠A), AD=AD (common side).
→ By SAS, △ABD ≅
△ACD. So BD=CD (CPCT) — AD bisects BC! (Median and angle bisector coincide in isosceles
triangle!)
| Criterion |
What you need |
Key memory tip |
| SSS |
All 3 sides equal |
3 sides → definitely congruent |
| SAS |
2 sides + INCLUDED angle |
Sandwich angle between the 2 sides |
| ASA |
2 angles + INCLUDED side |
Sandwich side between the 2 angles |
| AAS |
2 angles + any one side |
If 2 angles known, 3rd can be found → then use ASA logic |
| RHS |
Right ∠ + hypotenuse + one side |
ONLY for right triangles |
| AAA |
3 angles |
❌ NOT sufficient (gives similar, not congruent) |
| SSA |
2 sides + non-included angle |
❌ NOT sufficient (ambiguous case) |
Section A — Identify the Criterion Easy
- Q1. △ABC and △DEF have AB=DE, BC=EF, ∠B=∠E. Which criterion
of congruence applies?
- Q2. △PQR and △XYZ have ∠P=∠X, ∠Q=∠Y, QR=YZ. Which
criterion?
- Q3. Right △ABC (right angle at B) and right △PQR (right
angle at Q), hypotenuse AC = PR, BC = QR. Criterion?
- Q4. △LMN has LM=LN=7cm and △PQR has PQ=PR=7cm, and
MN=QR=10cm. Criterion?
- Q5. △ABC and △FGH: ∠A=∠F=60°, ∠B=∠G=70°, AB=FG. Criterion?
- Q6. Is it possible to conclude congruence from only: ∠A=∠P,
∠B=∠Q, ∠C=∠R? Why or why not?
Section B — Prove Congruence Medium
- Q7. In quadrilateral ABCD, AB=AD and BC=DC. Prove △ABC ≅
△ADC.
- Q8. In isosceles △ABC where AB=AC, D is midpoint of BC.
Prove △ABD ≅ △ACD. What can you conclude about AD?
- Q9. Two triangles share a common side PQ. △PQR and △PQS lie
on opposite sides of PQ with PR=PS and QR=QS. Prove △PQR ≅ △PQS.
- Q10. In △ABC, ∠B=∠C and D is the midpoint of BC. Prove △ABD
≅ △ACD.
- Q11. In the figure, two lines PQ and RS bisect each other
at O. Prove △POR ≅ △QOS.
- Q12. PA and PB are two tangents drawn from external point P
to a circle with centre O. OA⊥PA and OB⊥PB, OA=OB. Prove △OAP ≅ △OBP.
Section C — Find Unknown Values Medium
Q13. △ABC ≅ △PQR. AB=3x+1, PQ=4x-2. Find x and AB.
Q14. △DEF ≅ △KLM. ∠E = 5y+10, ∠L = 3y+30. Find y and both
angles.
Q15. If △ABC ≅ △DEF and perimeter of △ABC = 24 cm, find
perimeter of △DEF.
Q16. △PQR ≅ △STU. PQ=5cm, QR=7cm, PR=9cm. Find ST+TU+SU.
Section D — Higher Order Hard
- Q17. In △ABC, altitudes BD and CE are drawn to sides AC and
AB respectively. If BD=CE, prove that △BCD ≅ △CBE. Hence prove △ABC is isosceles.
- Q18. In a quadrilateral PQRS, PQ=RS and PS=QR. Prove that
△PQS ≅ △RQS. What type of quadrilateral is PQRS?
- Q19. ABCD is a square. Prove that △ABD ≅ △CBD and hence
show diagonal BD bisects ∠B and ∠D.
- Q20. In △PQR, PQ=PR. If S is any point on QR, prove that
∠PSQ + ∠PSR = 180°. (Hint: Use properties of isosceles triangle.)
- Q21. Two right triangles have hypotenuse 10 cm each and one
leg 6 cm each. Are they necessarily congruent? Which criterion?
- Q22. In △ABC, AB=AC. A point D is on AC such that BD=BC.
Prove △ABD ≅ △ABC? Will this work? Why or why not?
- Q23. ABCD is a rectangle. Diagonal AC = diagonal BD. Prove
△ABC ≅ △DCB.
- Q24. In △XYZ, XY=XZ. Perpendicular XM is drawn to YZ. Prove
YM=MZ using congruence. What do you conclude?
- Q25. △OAB and △OCD are congruent with OA=OC and OB=OD.
Prove that AB=CD.
- Q26. ABC is a triangle right-angled at C. D is the midpoint
of hypotenuse AB. Prove CD = (1/2)AB using coordinates or congruence.
✅ Key Answers: Q1: SAS | Q2: AAS | Q3: RHS | Q4: SSS | Q5: ASA | Q6: No — only AAA,
not sufficient | Q13: x=3, AB=10cm | Q14: y=10, both 60° | Q15: 24cm | Q16: 21cm | Q21: Yes, by RHS
criterion
📝 Quick Revision
- Congruent figures: same shape AND same size (≅ symbol); CPCT — corresponding parts of congruent
triangles are equal
- SSS: 3 sides equal | SAS: 2 sides + included (between them) angle
equal
- ASA: 2 angles + included (between them) side equal | AAS: 2 angles
+ any side
- RHS: Right angle + Hypotenuse + one Side (for right triangles only)
- ❌ AAA proves similarity, NOT congruence | ❌ SSA is not a congruence criterion
- In proof: State given, state what we need to prove, write "In △___ and △___:", list equal parts,
state which criterion, conclude congruence, then use CPCT if needed