Q35 (a). There is a circular park of diameter 65 m where AB is
a diameter. An entry gate is to be constructed at a point P on the boundary such that distance of P
from A is 35 m more than the distance of P from B. Find distance of point P from A and B
respectively.
Let \(BP = x\), \(AP = x + 35\). Angle in semicircle: \(\angle APB = 90�\).
\((x+35)^2 + x^2 = 65^2 \Rightarrow 2x^2 + 70x - 3000 = 0 \Rightarrow x^2 + 35x - 1500 = 0\).
\((x + 60)(x - 25) = 0 \Rightarrow x = 25\). So \(BP = 25\) m, \(AP = 60\) m.